An elevator is traveling from the lobby to top of a building as it slows stop on floor what happens your apparent weight?

When an elevator is slowing down to stop on a floor, your apparent weight will be greater than your actual weight. This is because the elevator is exerting a force on you in the upward direction, which is added to your weight due to gravity. The net force acting on you is therefore greater than your weight, resulting in an increased apparent weight.

As the elevator comes to a stop, your apparent weight will be equal to your actual weight. This is because the elevator is no longer exerting any additional force on you, so the net force acting on you is simply your weight due to gravity.

Once the elevator starts moving up again, your apparent weight will be less than your actual weight. This is because the elevator is now exerting a force on you in the downward direction, which is subtracted from your weight due to gravity. The net force acting on you is therefore less than your weight, resulting in a decreased apparent weight.

The amount by which your apparent weight changes depends on the acceleration of the elevator. The greater the acceleration, the greater the change in your apparent weight.

For example, if the elevator is accelerating at a rate of 2 m/s^2, your apparent weight will be 20% greater than your actual weight when the elevator is slowing down to stop, and 20% less than your actual weight when the elevator is starting to move up again.

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